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February 1, 2008

Modular Forms

Posted by John Baez

Jim Dolan and I are trying to learn about modular forms and the Modularity Theorem, once known as the Taniyama–Shimura–Weil Conjecture. It’s an irresistible challenge. After all, this result implies Fermat’s Last Theorem, but it’s much more conceptual, and closely related to the Hecke operators we’re always talking about.

I think we’re making decent progress — Diamond and Shurman’s book is very helpful. But, I’m still lacking in intuition in many ways.

For example: I think I have a decent intuition for level-1 modular forms. It took me about 10 years. Now I want to understand higher levels equally well. I’m hoping it won’t take another decade.

Maybe I should say where I am.

I have a good picture of the moduli space of elliptic curves, H/SL(2 ,). I’m friends with the Eisenstein series g 2 and g 3 . I know they generate the ring of level-1 modular forms, and I know why the discriminant Δ=g 3 2 27 g 2 3 generates the ideal of cusp forms.

Say we go up to level two, replacing SL(2 ,) by the Hecke subgroup Γ 0 (2 ). I want an equally clear story in this case. What does the moduli space H/Γ 0 (2 ) look like? How many cusps does it have? What is the ring of level-2 modular forms like? What are some explicit generators and relations? What are the cusp forms like, in terms of these generators?

Presumably this information is buried in many places, e.g. in the chapter ‘Modular forms for Hecke subgroups’ of Knapp’s Elliptic Curves. These sources seem to tackle all levels at once. But I’m feeling lazy, so I’d like someone to just tell me what’s going on at level 2.

It would also be nice to see a kind of chart showing how things work for low levels.

Posted at February 1, 2008 7:29 PM UTC

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39 Comments & 1 Trackback

Re: Modular Forms

I’m not fully sure about this stuff but I think I understand it well enough at level 2. The moduli space looks like a Riemann sphere with three holes poked in it. (I think they’re actually called cusps, but I think of them as holes poked in the surface)

There are two level-one modular forms, which I know how to get in two ways:

The fourth powers of the Jacobi theta functions at z=0–there are three values but the fourth powers are not linearly independent, and the Jacobi identity brings it to two, or

The Weierstrass p functions at 1/2, τ/2 , and (τ+1 )/2 (when you take 1 and τ to be the periods rather than the half-periods–I don’t know what the convention is), which always add up to 0. Also note that those three points are also precisely the points(modulo periods) where the derivative is zero.

Either basis can be described in terms of the other(and I think the Wikipedia pages describe how exactly to do that).

Higher-order(I can’t remember the exact term) modular forms are expressed in terms of these, and you can tell when it’s level-1 when you get one symmetric in the three generators. (That’s why you use three instead of two, despite only two being linearly independent)

There’s one fundamental modular function, the elliptic lambda, which takes values 0, 1, and infinity on the cusps.

I’m not fully sure about levels 3 and higher(most of this stuff I figured out myself/with the help of Wikipedia/MathWorld a few years ago, and I’m only seventeen so I probably shouldn’t know this at all, and take it with a grain of salt) but I do know that there’s a really nice link to Platonic solids on levels 3, 4, and 5. Can’t really tell you much more than what the moduli spaces look like, though.

On levels 3-5 the moduli space is a Riemann sphere with cusps.

On level 3, there are 4 cusps, the vertices of a tetrahedron.

On level 4, there are 6 cusps, the vertices of an octahedron.

On level 5, there are 12 cusps, the vertices of an icosahedron.

On level 6, you have a torus. I don’t remember how many cusps it has but if you fill in all the holes it’s isomorphic to the plane modulo the Eisenstein integers(or, in elliptic curve form, x 3 1 =y 2 )

On level 7 you have the Klein quartic. There are 24 cusps, related to tiling the quartic with heptagons and/or triangles.

And after that my knowledge is pretty much exhausted.

Posted by: William on February 1, 2008 11:33 PM | Permalink | Reply to this

Re: Modular Forms

William said:

On level 6 you have a torus. I don’t remember how many cusps it has

12. 6 only has 2 units, so each member of the “projective line” over 6 gets one hexagon. It’s actually quite easy to build the correct labelling starting from a hexagonal tiling of the plane. Label two adjacent tiles with 0 and , and just keep applying the rules that rotating by 60 degrees about the hexagon adds 1 to everything, while the 180 degree rotation that switches 0 and sends every q1 q.

It’s helpful to build a table of equivalent fractions first, so that you can see at a glance that, for instance, 5 2 =1 4 (mod 6, of course).

It then also becomes obvious that the clumps of 12 hexagons give the tiling of the plane by equilateral triangles (that’s the A 2 lattice, isn’t it?)

Posted by: Tim Silverman on February 6, 2008 11:50 PM | Permalink | Reply to this

Re: Modular Forms

William wrote:

I’m not fully sure about this stuff but I think I understand it well enough at level 2. The moduli space looks like a Riemann sphere with three holes poked in it. (I think they’re actually called cusps, but I think of them as holes poked in the surface.)

I just now happened to bump into a picture of the fundamental domain for level 2 – it’s on page 260 of Knapp’s Elliptic Curves. He says “A feature of this diagram is that S(R) and ST(R) contribute to the same cusp. Thus there are only two cusps, at and 0 , even though [SL(2 ,),Γ 0 (2 )]=3 .”

So, it’s possible that the third ‘hole’ you’re talking about is not really what people call a cusp, but instead some other funny spot.

For example, at level 1, the moduli space looks like a Riemann sphere with one hole poked out of it — the cusp — but there are also two other funny spots, corresponding to the lattices with square symmetry and hexagonal symmetry — the Gaussian integers and the Eisenstein integers. Those other spots aren’t really cusps.

There are two level-one modular forms, which I know how to get in two ways:

I’m confused. Do you mean level-two?

By the way, my favorite level-2 modular form is the ‘cross ratio’. People usually think of that as an invariant of 4 points on the Riemann sphere, but you can reinterpret it as an invariant of elliptic curves with a little extra structure, as I explained near the end of week229. There’s a lot more about this in Lecture 9 of Dolgachev’s course. I guess I should re-read this now and see if I understand it better.

Higher-order (I can’t remember the exact term) modular forms are expressed in terms of these,

I think the term you want is ‘weight’.

I’m only seventeen so I probably shouldn’t know this at all…

Right — you should be out having sex and doing drugs, or whatever 17-year-olds are supposed to do these days.

On level 3, there are 4 cusps, the vertices of a tetrahedron.

On level 4, there are 6 cusps, the vertices of an octahedron.

On level 5, there are 12 cusps, the vertices of an icosahedron.

On level 7 you have the Klein quartic. There are 24 cusps, related to tiling the quartic with heptagons and/or triangles.

Cool! Incredible! I suspect these points aren’t all ‘cusps’ in the technical sense, but I think you’re on to something here… for example, I know that PSL(2,5) is the symmetry group of the dodecahedron, and PSL(2,7) is the symmetry group of the Klein quartic. Klein spent a lot of time studying both these things.

Speaking of cusps and the Klein quartic. I have a webpage on the Klein quartic, in which I claim this curve is the upper halfplane H mod the group Γ(7 )… and a while ago someone sent me an email saying that’s not quite right: you need to add on one point, a cusp, to get the Klein quartic. I can’t find that email now, but I think it sounds right. However, that suggests there’s just one cusp, and 23 other funny spots, for a total of 24 — the 24 vertices of this thing:

Thanks to Greg Egan for this moving picture!

(I’m sort of confused about Γ(7 ) versus Γ 0 (7 ), now.)

Posted by: John Baez on February 2, 2008 1:00 AM | Permalink | Reply to this

Re: Modular Forms

So that William doesn’t feel too bad, I will add that his understanding corresponds to mine (right down to the holes poked in the surface). Of course, I’m just another amateur, so what I’m about to say may very well be completely idiotic, but the urge to babble has become irresistable, so here goes.

My understanding (if you can call it that) is that the inclusion of Γ(N) in the modular group Γ gives rise to a covering of H/Γ by H/Γ(N), and lifting the fundamental domain of Γ to the covering gives a tiling of the surface by regular N-gons, 3 meeting at each vertex, each subdivided into N triangles corresponding to the fundamental domain of the modular group, From this, it ought to be obvious that the cusps correspond to the centres of the faces. So if that’s not true, then something has going terribly wrong …

I thought that, except for the case of level 2, there are N 2 2 pN(1 1 p 2 ) N-gons (taking the product over all prime factors p of N, each counted once. (In fact I’m sure I read this, or something like it, in Diamond and Shurman, only of course now I can’t find it.) This does agree with what William said about the Platonic solids. The faces can, I believe, be labelled by lines through the origin of the free 2-dimensional module over N, although in general, these labels will appear on multiple faces. (For prime N, these will be points in the projective line over the field with N elements; otherwise they will be somewhat wackier points in a generalised “projective line” over a ring. E.g. for N=6 we get points 0 , 1 , 2 , 3 , 4 , 5 , 1 2 , 1 3 , 2 3 , 1 4 , 3 4 and .)

However, the action of Γ/Γ(N) will be consistent over where it sends the labels. So, for instance, the 24 faces of the Klein quartic can be labelled with the 8 points in the projective line over 𝔽 7 , each appearing three times, and if a member of SL(2,7 ) sends, say one face labelled with 2 to a face labelled with , then it will send all three faces labelled with 2 to faces labelled with .

The modular group will then act as automorphisms of the tiling. The generator sending zz+1 will rotate the faces labelled with by one step (ie one Nth of a full rotation), the generator sending z1 z will rotate 180 degrees about the edge(s) connecting the face(s) labelled with and the face(s) labelled with 0 , and likewise, order three elements rotate about vertices.

As William said, I thought at level 2, we get the tiling of the Riemann sphere with regular bigons, three meeting at each vertex, giving 3 faces (labelled with 1, 0 and ), 2 vertices and 3 edges.

Or perhaps this is all baloney.

Hmm, looking at what you said again, you’re talking not about Γ(2 ), but about Γ 0 (2 ). That might account for the confusion. At least, if it did, I am less likely to be humiliated and equally likely to learn something when a genuine professional turns up to explain things. So I’m keeping my fingers crossed.

Posted by: Tim Silverman on February 2, 2008 4:33 PM | Permalink | Reply to this

Re: Modular Forms

Ha! Diamond and Shurman, §3.8 (“More on cusps”) verifies at least the algebraic part of this, and goes into more detail.

On other elliptic points: the point at i of order 2 lifts to the midpoints of edges, while the point of order 3 at ω (or ω 2 if we take the other boundary of the fundamental domain) lifts to the vertices of the tiling.

Posted by: Tim Silverman on February 2, 2008 9:31 PM | Permalink | Reply to this

Re: Modular Forms

…we get the tiling of the Riemann sphere with regular bigons, three meeting at each vertex, giving 3 faces (labelled with 1, 0 and ∞), 2 vertices and 3 edges.

Yeah, the Grothendieck ribbon graph associated to the j-invariant!!! Cool!

Posted by: Kea on February 3, 2008 5:45 AM | Permalink | Reply to this

Re: Modular Forms

Yes, that is certainly is one of the most fascinating themes in mathematics. Esp. the use of modular functions to build class fields in analogy to the use of the exponential function to produce roots of unity. Here a nice article. I found this book on that very thrilling. One of the IMHO most astonishing things is the existence of analoga over finite fields, e.g. here the “algebraist’s upper half plane”, related to other strange things. A beautifull introduction into such developments is the last chapter of Vladut “Kronecker’s Jugendtraum and Modular Functions”. Finally a related ppt and here and here articles about the strange conections between modular functions and continued fractions and Y.I. Manins “Alterstraum”.

Posted by: Thomas Riepe on February 2, 2008 4:35 PM | Permalink | Reply to this

Re: Modular Forms

And yes, I meant level-two rather than level-one. I meant weight-one or weight-two there, anyways.

Posted by: William on February 2, 2008 7:18 PM | Permalink | Reply to this

Re: Modular Forms

OK, got a little more.

The labels on the cusps of Γ(N) are precisely those members of the group N 2 which are of order N, modulo negation. This means that we get a labelling by lines through the origin of the N-module N 2 , each of which appears a number of times equal to half the order of the group of units in N. So twice in the case of Γ(5 ), three times in the case of Γ(7 ), once for Γ(3 ), Γ(4 ) and Γ(6 ). (Γ(2 ) is slightly different.)

Now, in the case of Γ 1 (N), we mod out by the action of the group generated by zz+1 . So the N-gon(s) labelled by fold down to a single triangle made into a cone, with the cusp at its apex. (The triangles, I neglected to mention, have bases on the edges of the N-gon, and apices at its centre.) The faces labelled with integers all collapse into a single N-gon. Other faces (if any) may undergo various other forms of collapse.

In the case of Γ 1 (2 ), the faces labelled with 0 and 1 become identified, so we get left with 2 cusps, one at 0 (or 1 ) and one at .

In the case of, say, Γ 1 (4 ), we get a cusp on the face, a cusp on the “integer” face (which results from identifying 0, 1, 2 and 3) and a cusp on the 1 2 face.

Some of these cusps (not to mention the other elliptic points) get folded over in various ways which probably do things do their order that I haven’t worked out yet.

I still haven’t understood Γ 0 (N). It’s obviously somewhere in between the other two, but it seems to be more complicated than either.

Posted by: Tim Silverman on February 3, 2008 12:45 PM | Permalink | Reply to this

Re: Modular Forms

I burbled

Some of these … elliptic points … get folded over …

I was very very confused here. It’s perfectly obvious from the tesselation picture that the lifts of the elliptic points get completely unfolded, so Γ(N) doesn’t have any elliptic points for N>1 . Larger congruence subgroups may leave some elliptic points still folded over, in which case they will retain their periods of 2 or 3. (However, Γ 1 (N) doesn’t in fact have any elliptic points for N>3 . As yet, it’s only semi-clear to me intuitively why this is so. )

Posted by: Tim Silverman on February 5, 2008 8:33 PM | Permalink | Reply to this

Re: Modular Forms

JB wrote:

PSL(2,5) is the symmetry group of the dodecahedron, and PSL(2,7) is the symmetry group of the Klein quartic

Yes, and PSL(2,3) is the symmetry group of the tetrahedron (A 4 ) and PSL(2,2) is the symmetry group of the tiling of the sphere by three bigons (S 3 ) and the group that one might call PSL(2 , 4 ) (linear transformations of N× N of determinant 1, mod {1,1 }) is the symmetry group of the cube (S 4 ).

(Is there any deep reason for that progression of symmetric and alternating groups S 3 , A 4 , S 4 , A 5 , other than numerical coincidence?)

Posted by: Tim Silverman on February 3, 2008 12:56 PM | Permalink | Reply to this

Re: Modular Forms

All these comments are great! I’m supposed to be writing a paper, so I’m trying not to blog too much. I will read these more carefully and reply when I feel like taking a break and having some fun.

Posted by: John Baez on February 4, 2008 3:22 AM | Permalink | Reply to this

Re: Modular Forms

Conc. math related funreading:
Here a book about the crime case behind this painting. The author Bernd Roeck is a well known historian and claims after studying old archives that Piero della Francesca’s “The Flagellation” is a painted testimony of a political murder case, where Federico da Montefeltro killed his stepbrother Oddantonio.

Conc. modular forms, Mumford’s article on compactifying the “universal elliptic curve” above a modular curve in “Smooth compactification of locally symmetric varieties” is very beautifull to read. By a “scissors and glue” construction instead of refering to general theorems he compactifies it in a very intuitive way with toric varieties, i.e. schemes over F1.

Posted by: Thomas Riepe on February 6, 2008 11:23 AM | Permalink | Reply to this

Re: Modular Forms

Tim writes:

My understanding (if you can call it that) is that the inclusion of Γ(N) in the modular group Γ gives rise to a covering of H/Γ by H/Γ(N), and lifting the fundamental domain of Γ to the covering gives a tiling of the surface by regular N-gons, 3 meeting at each vertex, each subdivided into N triangles corresponding to the fundamental domain of the modular group.

I’m way behind you, so let’s see if you (or anyone!) can help me unnderstand this.

For our TV viewers out there, let’s first recall that Γ is the group of 2 ×2 matrices with integer entries having determinant 1, better known as SL(2 ,). Or, maybe it’s this group modulo ±1 , better known as PSL(2 ,). Which group we use doesn’t matter a lot for what we’re doing now, as long as we’re consistent about it. So, let me not mod out by ±1 , at least in this comment.

Then Γ(N) is the subgroup of Γ=SL(2 ,) consisting of those matrices whose entries are equal, mod N, to those of the identity matrix.

This is a normal subgroup, and I guess

Γ/Γ(N)=SL(2 ,/N)

at least when N is prime. Is this right? Does this make sense when N is not prime?

Γ and thus Γ(N) acts on the upper halfplane H, and we’re mainly interested in H/Γ(N), which is a covering space of H/Γ.

I know and love H/Γ, and I want to know and love H/Γ(N).

So, I’ll do what you say and think of H/Γ(N) as a covering space of HΓ. Or, equivalently, I’ll think about a fundamental domain for the action of Γ(N) on H as made of a bunch of fundamental domains for the action of Γ on H.

Here are a bunch of fundamental domains for the action of Γ on H:

The gray one is everybody’s favorite. It’s a ‘triangle’ with two corners having 60-degree angles and one corner infinitely far up the page with a 0-degree angle — that very pointy corner is what gives the ‘cusp’.

So, how do I create a fundamental domain for Γ 0 (N) by taking a bunch of fundamental domains for Γ?

For starters, how many do I need? It must be the cardinality of Γ/Γ 0 (N), no? That should be the cardinality of SL(2 ,/N), no? At least when that makes sense?

But wait — now I think the right answer is the cardinality of PSL(2 ,/N). We really need to think about groups that act faithfully on H, so we need to mod out by ±1 everywhere.

Which is it?

Let’s see: what’s the cardinality of SL(2 ,/p)? First, what’s the cardinality of GL(2 ,/p)? There are p 2 1 choices for the first row of the matrix, and p 2 p choices for the second row. So, (p 2 1 )(p 2 p). Of these matrices, 1 /(p1 ) of them have determinant 1. So, there are

(p+1 )(p 2 p)=p 3 p

matrices in SL(2 ,/p).

Let me check — I usually make mistakes in calculations like this. For p=2 , this formula gives 6, which fits the idea that SL(2 ,/2 )=PSL(2 ,/2 )=S 3 .

For p=5 this formula gives 120 , which matches the idea that PSL(2 ,/5 ), half as big, is A 5 .

This also fits your formula which says that for prime p, there’s a tiling of H/Γ 0 (N) by

p 2 2 (1 1 /p 2 )

N-gons, each of which consists of 2 p triangles, for a total of

p 3 p

triangles. Sort of like this for p=7 :

I believe there are 7 3 7 =336 triangles in this picture: 14 triangles per heptagon, 24 heptagons in all. If I’m wrong, I must be making a serious mistake somewhere.

Hmm, so the number of triangles is the cardinality of SL(2 ,/N), not PSL(2 ,/N)? At least when N is prime?

Anyway, I eventually wish to get to more interesting questions, but for now let me quit while I’m ahead (or behind).

Posted by: John Baez on February 7, 2008 5:49 PM | Permalink | Reply to this

Re: Modular Forms

The main next things I’d like to do are:

  • Really understand the roles of SL(2 ,/N) versus PSL(2 ,/N) in this situation, at least when N is prime. And do they make sense when N isn’t prime?
  • At least for N=p an odd prime, see why the p 3 p triangles tiling H/Γ(N) organize themselves into p-gons with 2 p triangles each, for a total of 1 2 (p 2 1 ) p-gons.
  • Figure out how many of these p-gons meet at each vertex. It seems to be 3 a lot of the time. Is it always 3?
  • If it’s always 3 p-gons meeting at a vertex, I can calculate the genus of H/Γ(p), and see why we’re getting genus 0 (a sphere) for p=3 and 5 , but genus 3 (a 3-holed torus, shown writhing above) for p=5 .
  • It would then be fun to understand p=11 — some sort of surface tiled by 120 hendecagons.
  • Of course, non-prime N are also interesting.
Posted by: John Baez on February 7, 2008 7:12 PM | Permalink | Reply to this

Re: Modular Forms

JB wrote

I’m way behind you

That’s a slightly surreal and very scary position for me to find myself in. Some of this is stuff I think I actually know, but lots of it is just strung together with connections that seem intuitively plausible, backed up by some numbers and groups I’ve calculated that turn out to match the answers in the books…

That said, let me make a couple of things clear which might have confused some of our readers. First, I’m only going to talk about Γ(n), which I think I sort of understand, and not Γ 0 (N) or Γ 1 (N), which I’m much less clear about. Second, it’s as well to be explicit that there are two kinds of triangle that we are talking about. We can, for instance, take the fundamental domain of the modular group—the grey triangle in the first diagram above. Or we can slice it vertically up the middle to get two triangles—that’s also the kind of triangle in the second diagram, the one where the triangles are coloured. Obviously there are twice as many of the second type of triangle, so we need to be clear which kind we’re talking about. In my earlier posts, I was always talking about the first kind.

So that gives us the number of elements in PSL(2 ,N), which is what I want. And yes, it does appear, from my not very rigorous or thorough investigations, that this can be made to work for non-prime N. We just have to think carefully about the points in N 2 , and the effect on them of matrices taking values in N, and multiplication by scalars in N.

Darn. There’s plenty more I wanted to say, but it’s getting late, so maybe I’ll talk more tomorrow. In the meantime, I can refer you back to §3.8 of Diamond and Shurman, which is full of excellent stuff.

Posted by: Tim Silverman on February 7, 2008 10:32 PM | Permalink | Reply to this

Re: Modular Forms

Concerning PSL(2 , N) for non-prime N: the problem you might expect is that, since there are non-zero elements of N that are not invertible, there are matrices in M 2 ( N) that have non-zero determinants but are not invertible. But we don’t care about these matrices: we only care about matrices of determinant 1 , which certainly are invertible. So at least we don’t have to worry about this particular problem.

Posted by: Tim Silverman on February 8, 2008 5:20 PM | Permalink | Reply to this

Re: Modular Forms

Good point.

Posted by: John Baez on February 8, 2008 5:40 PM | Permalink | Reply to this

Re: Modular Forms

Tim wrote:

That’s a slightly surreal and very scary position for me to find myself in.

I was trying to reassure you, not frighten you!

In the meantime, I can refer you back to �3.8 of Diamond and Shurman, which is full of excellent stuff.

Unfortunately Jim Dolan has that book checked out… but actually it’s not so bad: I’m more interested in chatting and doing calculations to build up my intuition, rather than looking up a bunch of facts.

First, I’m only going to talk about Γ(n), which I think I sort of understand…

That’s fine. Knapp seems to focus on the groups Γ 0 (n). This, and the fact that they’re called ‘Hecke subgroups’, seems to suggest they’re especially important. But I don’t know why… and I agree with you that the groups Γ(n) seem easier to start with. So, let’s think about those!

Second, it’s as well to be explicit that there are two kinds of triangle that we are talking about. We can, for instance, take the fundamental domain of the modular group — the grey triangle in the first diagram above. Or we can slice it vertically up the middle to get two triangles - that’s also the kind of triangle in the second diagram, the one where the triangles are coloured.

Okay, great! — that should clear up the annoying factor of 2 that’s been bugging me, which is related to my perpetual confusion about SL(2 ) versus PSL(2 ) versus GL(2 ) versus PGL(2 ).

For example, consider the dodecahedron. We can chop each of its 12 pentagons into 10 right triangles, for a total of 120.

This is called the “Coxeter complex” for the group of all rotation and reflection symmetries of the dodecahedron — a 120-element group. The reason is that the set of these triangles forms a torsor for this group: given any two of these triangles, there exists a unique element of this group sending the first triangle to the second!

On the other hand, we can chop each of the dodecahedron’s 12 pentagons into 5 triangles, for a total of 60. Each of these triangles is built from two of the former triangles. The set of these triangles is a torsor for the group of rotation symmetries of the dodecahedron — a 60-element group.

This 60-element group is

PSL(2 ,/5 )Γ/Γ(5 )A 5 ,

and indeed the whole story here is the p=5 case of the general theory I’m trying to understand.

It looks like the 120-element group of all rotation and reflection symmetries of the dodecaheron is some other, not so relevant group. I guess it’s

PSL(2 ,/5 )×/2 A 5 ×/2 ,

because the extra symmetry (x,y,z)(x,y,z) commutes with all the rotational symmetries of the icosahedron. And, I guess this group is not isomorphic to PGL(2 ,/5 ), because that 120-element group is isomorphic to S 5 . Could this group be isomorphic to SL(2 ,/5 )? I guess so!

(I’m digressing. I just always get confused about this SL(2 ) versus PSL(2 ) versus GL(2 ) versus PGL(2 ) stuff.)

So, you’ve convinced me that the relevant tiling of H/Γ(p) is the one with fewer triangles, namely 1 2 (p 3 p) triangles. So, for p=7 , not this tiling with 7 3 7 =336 triangles:

but the one with 168 triangles, each twice as big — one for each element of PSL(2 ,/7 ).

Posted by: John Baez on February 8, 2008 6:35 AM | Permalink | Reply to this

Re: Modular Forms

John wrote:

Knapp seems to focus on the groups Γ 0 (n). This, and the fact that they’re called “Hecke subgroups”, seems to suggest they’re especially important.

Jim Dolan replied via email:

is the structure on a lattice that the hecke subgroup stabilizes (say for prime n) essentially just an “n-local flag” or something like that? (in this dimension “flag” is just a bombastic way of saying “non-trivial subspace”, right?)

i didn’t actually try to calculate this or check any fine print or anything.

That sounds right, since this group consists of “upper triangular matrices mod n”, and in general upper triangular matrices preserve a flag.

Posted by: John Baez on February 8, 2008 4:46 PM | Permalink | Reply to this

Re: Modular Forms

Jim wrote in reply to the above stuff:

whenever you have a “basic hecke operator” (aka “atomic geometric relationship”), there’s the “joint stabilizer” subgroup simultaneously stabilizing both of the features involved in the relationship; aka “intersection of the original stabilizers in the given relative position”. might this be what a “hecke subgroup” is, in general? so in this particular case, i’m imagining that maybe there’s a basic hecke operator something like “jump to an n-fold refinement of the lattice” (thought of as a random jump operator on lattices), and that the intersection of the two different sl(2,z)’s respectively stabilizing the original lattice and its n-fold refinement might be a “gamma_0(n)” or whatever it’s called; can you get something like that to work?

if this _is_ (more or less) what “hecke subgroups” are, then i’m a bit annoyed that i didn’t hear anyone say it outloud before. on the other hand the guess that i’m making here _is_ influenced by stuff gleaned from brown’s book, about the incidence geometry corresponding to the circular “augmented a_n series” dynkin diagrams.

Posted by: John Baez on February 8, 2008 6:10 PM | Permalink | Reply to this

Re: Modular Forms

Conc. Hecke operators:

Yuri I. Manin found in the 1970’s a very beautifull, elementary and intuitive way to understand the 1st homology group of a modular curve and the action of Hecke operators on it through ‘modular symbols’. Here recent research on them, apparently many other related, fascinating things hide there to be found .

Posted by: Thomas Riepe on February 16, 2008 12:28 PM | Permalink | Reply to this

Index of the Hecke algebra in its saturation; Re: Modular Forms

Excellent references, Thomas Riepe. Yuri I. Manin has discovered amazing things, and showed them to us clearly.

I have extracted and articulated an Integer Sequence which gives some of the flavor and data {do see the web page linked to, for its hotlinks and ability to show two graphs and the musical embodiment of the function}:

A135362 Index of the Hecke algebra in its saturation in End(J_0(n)).

n a(n)
40 1
41 1
42 1
43 1
44 2
45 1
46 2
47 1
48 1
49 1
50 1
51 1
52 1
53 1
54 3
55 1
56 2
57 1
58 1
59 1
60 2
61 1
62 2
63 1
64 2
65 1
66 1
67 1
68 2
69 1
70 1
71 1
72 2
73 1
74 1
75 1
76 2
77 1
78 2
79 1
80 4
81 1
82 1
83 1
84 2
85 1
86 1
87 1
88 8
89 1
90 1
91 1
92 16
93 1
94 4
95 1
96 8
97 1
98 1
99 9
100 1

OFFSET
40,5

COMMENT
“A quantity that controls the relation between the modular degree and congruences (the “congruence modulus”). This results in the following table, which suggests that if p | a(n) is a prime, then p^2 | 4 * n,a fact closely related to what Ken Ribet proved at the Raynaud birthday conference in Orsay a few years ago. Also, Mazur proved that a(p) = 1 when p is prime.”

LINKS
Yuri I. Manin, Iterated Modular Symbols.

William Stein, Modular Symbols, Modular Forms and Modular Abelian Varieties in MAGMA. See table p. 54.

PROGRAM
(MAGMA) function f(N) J := JZero(N); T := HeckeAlgebra(J); return Index(Saturation(T), T); end function; for N in [1..120] do print N, f(N); end for;

KEYWORD
nonn,new

AUTHOR
Jonathan Vos Post (jvospost3(AT)gmail.com), Feb 16 2008

Posted by: Jonathan Vos Post on February 19, 2008 5:20 PM | Permalink | Reply to this

Re: Modular Forms

John wrote:

So, you’ve convinced me that the relevant tiling of H/Γ(p) is the one with fewer triangles, namely 1 2 (p 3 p) triangles.

So, next I want to see why these triangles are organized into a bunch of p-gons, with p triangles per p-gon.

In other words: why does our tiling get a /p as a discrete rotational symmetry group?

For this, I guess we should use the fact that PSL(2 ,/p) acts on the set of triangles (in a free and transitive way). We should find a subgroup that looks like /p. And, the obvious candidate is the group generated by

T=(1 1 0 1 )

This matrix generates a subgroup of infinite order in SL(2 ,). In terms of the upper halfplane, this matrix acts by

ττ+1

So, it slides this picture one notch to the right:

In particular, it acts transitively on all the triangles like the gray one — the ones that share a vertex way up north, up at infinity… at the cusp.

So, when we work mod p, we get a similar picture, but with the cyclic group /p acting to cycle around p triangles that share a vertex — a cusp.

So, I see why you guys like the picture of a Platonic solid with each face chopped into triangles sharing a vertex at the face’s center… a cusp.

I think someone told me that for the case p=7 , there’s just one cusp. But that doesn’t seem to make sense now.

Posted by: John Baez on February 8, 2008 5:11 PM | Permalink | Reply to this

Re: Modular Forms

Yup. You’ve kind of followed the same reasoning that I used when working this stuff out, only backwards. I started out thinking, Well, mod N, that means the operation of adding 1 should wrap round on itself after N steps … and went on from there.

Maybe the guy who told you about the one cusp was thinking of the one cusp at which lifts to multiple cusps when we go to mod N.

Posted by: Tim Silverman on February 13, 2008 9:34 PM | Permalink | Reply to this

Re: Modular Forms

Tim wrote:

Maybe the guy who told you about the one cusp was thinking of the one cusp at which lifts to multiple cusps when we go to mod N.

Maybe that’s it. Let’s say that’s it.

(This is the problem with ‘learning math on the streets’…. rumors spread and get a bit more distorted with each retelling.)

If I weren’t so busy right now, I’d post another entry on modular forms. I’ve made a lot of progress, mainly thanks to talking with Jim. I guess I’ll talk about it when I get time.

One cool fact: the Modularity Theorem says each rational elliptic curve is the moduli space for elliptic curves equipped with some sort of extra structure. Very conceptual and self-referential! Amazing that Fermat’s Last Theorem is a corollary.

Posted by: John Baez on February 15, 2008 12:31 AM | Permalink | Reply to this

Re: Modular Forms

Even better, SL(2 ,) is generated by that matrix T above together with a matrix people call ST:

ST=(0 1 1 1 )

as discussed in week125. This matrix ST has order 6 in SL(2 ,) — in fact, it describes a 60 degree rotation in some weird basis. So, it has order 3 in PSL(2 ,).

Why is this “even better”? Because it means our tiling of H/Γ(n) will have 3-fold symmetry!

So, I’m feeling more confident that the tiling of H/Γ(n) consists of a bunch of p-gons — 1 2 (p 2 1 ) of them, to be precise — meeting three at at corner.

Check:

p=3 gives us 4 triangles meeting 3 at a corner — the tetrahedron.

p=5 gives us 12 pentagons meeting 3 at a corner — the dodecahedron.

p=7 gives us 24 heptagons meeting 3 at a corner — Klein’s quartic.

p=11 gives us 60 hendecagons meeting 3 at a corner — something I’d like to get to know.

I want to compute the genus of all such surfaces, which will be easy if this picture is correct. And, I should do some non-prime cases too! N=4 should give us the cube, according to William. But I have to get to work… can’t have fun like this all day.

Posted by: John Baez on February 8, 2008 5:57 PM | Permalink | Reply to this

p = 11 case is in the Math-Chemistry literature; Re: Modular Forms

The p = 11 case is in the literature after all – by Chemists!

“The undecakisicosahedral group and a 3-regular carbon network of genus 26”, by Erwin Lijnen, Arnout Ceulemans, Patrick W. Fowler, and Michel Deza

Abstract:

Three projective special linear groups PSL(2,p), those with p = 5, 7 and 11, can be seen as p-multiples of tetrahedral, octahedral and icosahedral rotational point groups, respectively. The first two have already found applications in carbon chemistry and physics, as PSL(2,5) ≡ I is the rotation group of the fullerene C_60 and dodecahedrane C_20H_20, and PSL(2,7) is the rotation group of the 56-vertex all-heptagon Klein map, an idealisation of the hypothetical genus-3 “plumber’s nightmare” allotrope of carbon.
Here, we present an analysis of PSL(2,11) as the rotation group of a 220-vertex, all 11-gon, 3-regular map, which provides the basis for a more exotic hypothetical sp^2 frame-work of genus 26. The group structure and character table of PSL(2,11) are developed in chemical notation and a three dimensional (3D) geometrical realisation of the 220-vertex map is derived in terms of a punctured polyhedron model where each of 12 pentagons of the truncated icosahedron is connected by a tunnel to an interior void and the 20 hexagons are connected tetrahedrally in sets of 4.
KEY WORDS: PSL(2,11), group theory, undecakisicosahedral group, topology, carbon allotrope
AMS: 05C10, 20B25, 57M20

1. Introduction

The three groups PSL(2,5), PSL(2,7) and PSL(2,11) form a special sub-set of the Projective Special Linear groups PSL(2,p) in view of their particular permutational structure. They can be viewed as multiples of the symmetry groups of the regular polyhedra in three dimensional (3D) space, and for this reason are also called the pollakispolyhedral groups [1]. PSL(2,5) and PSL(2,7) correspond to the pentakistetrahedral,
5_T, and heptakisoctahedral group,
7_O, respectively. Both have found applications in chemistry and physics….
[truncated]

Bingo! Does that fit the bill?

Now, can Greg Egan animate this into a screensaver of dazzling brain-twisting gorgeousness?

Posted by: Jonathan Vos Post on February 13, 2008 10:14 PM | Permalink | Reply to this

Re: Modular Forms

That’s interesting. On Tuesday, the mathematician Kostant visited UCR to talk about new connections between E 8 and the Standard Model — more about that later. At dinner, he reminded me that PSL(2,11 ) has a deep relation to another molecule: the buckyball! He has explained this here:

The buckyball is has icosahedral symmetry, so you might expect a relation to PSL(2,5 ), and there is — but it has a subtler relation to PSL(2,11 ).

Posted by: John Baez on February 15, 2008 4:45 AM | Permalink | Reply to this

Re: Modular Forms

Conc. “modular forms and L-series”:

When I thought about mentioning the connection between both as especially interesting, because in Hecke’s Theory the Mellin transform makes the functional equations of some L-series just the defining transformation rules of associated modular forms, I noticed that I know nothing about the p-adic analogon e.g. of the Mellin transform. Perhaps someone here knows where to look?

Concerning modular forms and critical L-values, here a descr. of a book by Shimura.

Posted by: Thomas Riepe on February 13, 2008 6:53 PM | Permalink | Reply to this

Re: Modular Forms

Thomas Riepe wrote:

Conc. “modular forms and L-series”:

When I thought about mentioning the connection between both as esp. interesting, because in Hecke’s Theory the Mellin transform makes the functional eq.s of some L-series just the defining transformation rules of associated modular forms, I noticed that I know nothing about the p-adic analogon e.g. of the Mellin transform. Perhaps someone here knows where to look?

I’m no expert, but at my current stage of development I find it reassuring to regard the Mellin transform as a silly trick — part of a cute but distracting ‘explicit formula’ for the transform mapping the Taylor series

n1 a nz n

to the Dirichlet series

n1 a nn z

Here’s how I’d prefer to think about it:

-valued functions on a sufficiently well-behaved monoid M form an algebra.

The algebra of Taylor series is the algebra of complex functions on the additive monoid of natural numbers.

The algebra of Dirichlet series is the algebra of complex functions on the multiplicative monoid of nonzero natural numbers.

Since these two monoids are both part of a single structure — the rig of natural numbers, the algebras of Taylor and Dirichlet series are part of a single algebraic structure: essentially, a ‘rig algebra’.

But, since most people have never thought about rig algebras, they jump back and forth between the two pieces of the rig algebra of with the help of the Mellin transform and its inverse.

Unfortunately this brings analysis into what is at its core a simple algebraic idea which would make sense with any field (e.g. the p-adics) replacing .

I’m overstating my case here, because at certain points the analytic aspects of the relation between modular forms and L-functions do become important — e.g. when we gain information about algebraic gadgets from poles and zeroes of L-functions that we can cook up from them. At least, that’s what everyone keeps saying.

But, I still find it amusing that people seem loathe to simply define a transform by saying it sends

n1 a nz n

to

n1 a nn z

and worry later about whether there’s an integral formula for this transform. After all, as soon as you get integrals into the game you start having to worry about when the integrals converge. I’d prefer to worry about that only when it becomes crucial.

Of course, when I learn more about this I may decide my current viewpoint is sort of childish.

(By the way, in the stuff above, a monoid is ‘sufficiently nice’ if for every element x there are finitely many pairs y,z with yz=x. We could avoid this issue by working with the monoid algebra [M], which you can think of as consisting of functions on M that vanish except at finitely many points. However, the Dirichlet series appearing in number theory usually have infinitely many nonzero terms, so I’m not taking that approach.)

Posted by: John Baez on February 13, 2008 6:56 PM | Permalink | Reply to this

Re: Modular Forms

Did’nt I see on this blog some days ago a now vanished question on a congruence of the Ramanujan tau numbers modulo 691 and how that relates to Galois representations? A cold prevented me to answer immediately, now here how I remember that and some links:

That congruence is a consequence of the Ramanujan conjecture, which was finally proved by Deligne. This conjecture is about estimating the coefficients of the Ramanujan function, a weight 12 modular form. If one Mellin-transforms that function into an L-series, these estimates of the coefficients look like similar estimates of coefficients in L-functions of the Weil conjecture. The later come from Galois representations on cohomology groups of varieties, so when one had no suitable verieties at hand, one looked for suitable else Galois representations. Eichler and Shimura were in part successfull with the Galois repr.s coming from the torsion points of the jacobians of modular curves. Then Deligne reduced the Ramanujan conjecture to the Weil conjecture by finding as suitable variety the “universal elliptic curve” above a modular curve. Like a usual ell. curve has torsion points, these universal curve have something like that (e.g. a representing scheme for the functor to the torsion points of each fiber). The first cohomology group of that thing with a sheaf of suitable weight finally solves the problem, and a Kuga-Sato variety (= a product of universal elliptic curves) connects it to the Weil conjecture. The Weil conjectures were proved by Deligne some years later.

Here and here Serres Bourbaki talks about the Ramanujan numbers and congruences coming from galois representations, here Delignes solution, here Brian Conrads lecture more detailed notes which use (and explain) the later and deeper “Weil II”. Here the very readable review article of Katz on Delignes proof of the Weil conjectures, here Katz lecture notes on “Weil-II” and finally here Katz general and simultaneous solution of congruence questions on coefficients of modular forms.

Posted by: Thomas Riepe on February 18, 2008 8:43 PM | Permalink | Reply to this

Re: Modular Forms

” Here the very readable review article of Katz on Delignes proof of the Weil conjectures…”

Oops, I meant this article. From the MathSciNet-review:

“This paper makes accessible to non-specialists the principal ideas in P. Deligne’s proof of the following fundamental result:

The author begins with an historical and motivational survey of this Riemann hypothesis, explaining the connection with formulae and inequalities for the number of solutions of equations over finite fields, the ideas behind the early proofs of special cases, the historical role of the Riemann hypothesis and the other Weil conjectures in the development of algebraic geometry, and the heuristic argument for the conjectures based on classical (characteristic 0) phenomena.

Concerning Deligne’s proof itself, the author spotlights two ingredients—(1) the monodromy of Lefschetz pencils, and (2) modular forms and Rankin’s method for studying the Ramanujan function and describes their fundamental roles in the proof. Deligne’s proof is then outlined in more detail in the special case of odd-dimensional non-singular hypersurfaces. Here monodromy, l-adic cohomology, Rankin’s method and L-series occupy a central place. The author discusses applications to the Ramanujan-Petersson conjecture, estimation of exponential sums in several variables, and the “hard” Lefschetz theorem. He concludes with a discussion
of open questions. The paper includes a lengthy bibliography.”

Posted by: Thomas Riepe on February 19, 2008 5:37 PM | Permalink | Reply to this

Re: Modular Forms

Aha, a discussion about the modular group!
See if I can join in.

Here are some of the things I learned lately.

First, about the relation between the quotients of gamma\n and other well known groups, such the cube, tetrahedron, Klein quartic. These groups are all automorphism groups of a
tessellation of triangles. I’ve displayed many of these tilings on my web page:
My page on geometry

If you compare at the triangles of let’s say the cube (or the octahedron) and that gamma\4, you see firstly that the number of triangles is the same. The corners are (pi/3, pi/2, pi/4) versus (pi/3, pi/2, pi/inf) respectively. So there is no conformal mapping between the tilings. However, there *is* a conformal mapping between gamma\4 and the “hyperbolic octahedron”, such as displayed here:
Hyperbolic Octahedron.