Linear Algebraic Groups (Part 7)
Posted by John Baez
One of the less obvious but truly fundamental realizations in group theory is the importance of the ‘parabolic subgroups’ of a linear algebraic group. Today we’ll sneak up on this realization using the example of .
We’ve already seen the Klein geometry corresponding to this group has important kinds of figures — points, lines, planes, etc. — whose stabilizers are certain nice groups called ‘maximal parabolic subgroups’ of . But there are also important figures build from these, like ‘a point lying on a line’, or ‘a line lying on a plane’. These are called ‘flags’, and their stabilizers are called ‘parabolic subgroups’. Today we’ll work out what these parabolic subgroups of are like. Especially important is the smallest one, called the ‘Borel’.
With this intuition in hand, we’ll want to generalize all these concepts to an arbitrary linear algebraic group. Amazingly, you can just hand someone such a group, and they can figure out the important kinds of geometrical figures in its Klein geometry, by determining its parabolic subgroups!
- Lecture 7 (Oct. 13) - Flags, and the flag variety , which consists of all chains of linear subspaces . The flag varieties as quotients of the general linear group by parabolic subgroups, which are intersections of maximal parabolic subgroups. The complete flag variety as the quotient where is the group of invertible upper triangular matrices, also called the Borel subgroup of . The cardinality of the complete flag variety over is the -factorial . When this reduces to the ordinary factorial, which counts ‘set-theoretic flags’.
As ever, the notes are due to John Simanyi. If you find mistakes, please let me know.
Re: Linear Algebraic Groups (Part 7)
It took me some years to decide that the basic theorem to start with is Borel’s, that if a connected affine solvable group acts on a complete (nonempty) variety , then there must be a fixed point. (Proof: has a subnormal chain with -dimensional affine subquotients, so the problem reduces to looking at such -d groups acting on smooth curves. Then those curves have to be genus , and there are only two cases to check.)
Hence if non-solvable acts on complete, any minimal orbit must be complete, hence (maximal solvable inside ) must have a fixed point on . So up to conjugacy, contains . It’s not as obvious that any is complete, just from .