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March 19, 2005

Derived Categories for Dummies, Part II

Posted by Urs Schreiber

I spent yesterday sitting on the beach at Vietri and reading Weibel, ‘An introduction to homological algebra’, trying to understand the details of derived functors. It takes many, many pages to really define them in detail, but here I try to summarize the key steps.

Last time I reviewed the definition of the derived category D(C)\mathbf D (C) of any abelian category CC. D(C)\mathbf D (C) is like the category K(C)\mathbf K (C) of (cochain) complexes in CC modulo chain homotopy but modded out by

(1)q:K(C)D(C) q : \mathbf K (C) \to \mathbf D (C)

(cf. Weibel 10.3.1)

which sends quasi-isomrphisms to true isomorphisms.

Now, given any additve functor

(2)F:CD F : C \to D

it lifts in the obvious way to a functor

(3)KF:K(C)KD. \mathbf K F : \mathbf K (C) \to \mathbf K D \,.

The problem is to turn this into a functor

(4)RF:D(C)D(D) \mathbf R F : \mathbf D (C) \to \mathbf D (D)

in a way that respects qq, i.e. which preserves quasi-isomorphisms.

So what one wants is to have an RF\mathbf R F which makes it true that there is a natural transformation from

(5)Fq F \circ q

to

(6)qRF. q \circ \mathbf R F \,.

If such an RF\mathbf R F exists it is called the total derived functor (10.5.1).

The idea here is simple enough. Things become more involved when this implicit definition of RF\mathbf R F is to be made more explicit. In order to do that the rest of the theory revolves around determining the cohomology of RF\mathbf R F.

So if RF\mathbf R F is applied to some cochain complex XX, what is the nn-th cohomology of the complex RF(X)\mathbf R F (X), i.e. what is the right hand side of

(7) nF(x):=H nRF(X) \mathbb{R}^n F(x) := H^n \mathbf R F(X)

?

Here the nF\mathbb{R}^n F are called the hyper-derived functors, by definition (5.7.4).

In order to understand hyper-derived functors it is finally necessary to first understand ordinary derived functors (to be distinguished from the ‘total’ derived functors that I started with).

So the idea is this:

Given any object AA in an abelian catgeory we can find resolutions of this object. A resolution is an exact cochain complex

(8)0AI 0I 1 0 \to A \to I^0 \to I^1 \to \cdots

which hence has H 0=AH^0 = A.

(This is familiar in physics from BRST quantization, where AA would be the space of physical states at ghost number 0.)

There are certain such resolutions which enjoy a property called injectivity. This is the case when each of the I nI^n is injective which in turn means that Hom(,I)Hom(\cdot,I) is an exact functor.

So here is what an ordinary right derived functor R nFR^n F does to an object AA:

(9)R nF(A):=H n(F(I A)) R^n F(A) := H^n(F(I_A))

it assigns to it the nnth-cohomology of the result of applying FF to any (fixed but arbitrary) injective resolution I AI_A of AA.

Fine, but that’s not enough. One needs to boost this construction by one dimension to get hyper-derived functors.

Given any chain complex AA, we can find its right Cartan-Eilenberg resolution, which is a (cochain) complex of cochain complexes, i.e. a double complex, with injective objects everywhere, being a resolution of the complex AA in analogy to the above construction in an appropriate sense. The nnth hypercohomology of this (the cohomology of the total complex) is the nnth hyper-derived functor of FF applied to R nF(A)\mathbf R^n F (A).

Using all this the implicitly defined total right derived functor RF\mathbf R F can be described finally as indicated at the beginning:

Its nnth cohomology is given by

(10)H nRF(X)= nF(X). H^n \mathbf R F (X) = \mathbb{R}^n F(X) \,.

Furthermore, if XX is the cochain representing an object xx then hypercohomology on XX coincides with cohomology

(11) nF(X)=R nF(X) \mathbb{R}^n F(X) = R^n F(X)

and at 0th position it reproduces FF applied to the original object

(12) 0F(X)=F(x). \mathbb{R}^0 F(X) = F(x) \,.

This gives the relation of the total derived functor RF\mathbf R F to the original functor FF.

Posted at March 19, 2005 11:46 AM UTC

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