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January 3, 2006

Bimodules, Adjunctions and the Internal Hom, Part II

Posted by Urs Schreiber

I continue where I left off yesterday.

Last time I reviewed some aspects of how every Frobenius algebra object in a monoidal category comes from an adjunction (which is a generalization by Aaron Lauda of a classical result in Cat\mathbf{Cat} to arbitrary 2-categories). One important point (for me at least) was that and how the 2-category of bimodules makes an appearance in this process.

There is another way to sort of ‘split an algebra in two adjoined halfs’. This, too, involves categories of modules showing up. It can most probably be related by some general nonsense to Aaron Lauda’s way of telling the story, but I don’t quite see yet how exactly.

What I am talking about is theorem 1 in

V. Ostrik
Module Categories, weak Hopf Algebras and Modular Invariants
math.QA/0111139.

Let again CC be some monoidal category. I’ll furthermore need to assume that CC is abelian and has a couple of further properties to be listed later.

In an abelian monoidal category we can take direct products and direct sums of objects and morphisms. Hence any such CC is like a categorified (semi)ring. From this point of view, it is natural to consider categorified modules for such a categorified (semi)ring.

Accordingly, a module category MM over CC is defined to be essentially a module in Cat\mathbf{Cat} over the (semi)ring object CC in Cat\mathbf{Cat}.

Hence there is a functor

(1)l:C×MM l : C \times M \to M

satisfying the usual properties of a usual left action up to coherent isomorphisms.

A straightforward example for a module category is the category of right modules over algebra objects in CC.

Let AA be an algebra object in CC and let mm be a right module over AA in CC. Then, clearly, for any object VCV \in C the object VmV \otimes m is again canonically a right module over AA.

Fixing some algebra object AA, we have the category Mod A(C)\mathrm{Mod}_A(C) of right AA modules in CC. By the above process, there is a left action of CC on Mod A(C)\mathrm{Mod}_A(C) and hence Mod A(C)\mathrm{Mod}_A(C) is a module category over CC.

It doesn’t hurt to pause for a moment and digest the different levels at which the notion of a module appears here and how one level gives rise to the other.

Now, the interesting point is that for many interesting cases, the above example for a module category is already essentially the only example, up to equivalence.

More precisely, there is the following theorem:

If CC is semisimple and rigid and if MM is semisimple and indecomposable (either guess what this means or look it up in the above paper)…
…then it is equivalent to a category of right modules Mod A(C)\mathrm{Mod}_A(C) for some algebra AA in CC

(2)MMod A(C). M \simeq \mathrm{Mod}_A(C) \,.

Now, we know that two algebra objects AA and AA' in CC are (essentially by definition) Morita equivalent iff their module categories are equivalent

(3)AMoritaAMod A(C)Mod A(C). A \overset{\mathrm{Morita}}{\simeq} A' \;\; \Leftrightarrow \;\; \mathrm{Mod}_A(C) \simeq \mathrm{Mod}_{A'}(C) \,.

Hence it follows (under the above stated assumptions) that specifying a (semisimple indecomposable) module category MM of a monoidal catgeory CC is the same as specifying a Morita class of algebra objects in CC.

Now what does this have to do with ‘splitting AA in two halfs’?

The answer is in the proof of the above theorem. This works as follows.

Recall that in a category with binary products (like the tensor product in the monoidal category CC) the functor

(4)IHom(Y,Z):ZZ Y \mathrm{IHom}(Y,Z) : Z \mapsto Z^Y

which maps (if it exists) any object ZZ to the exponential object which is the internal version of the ‘space of morphisms from YY to ZZ’ is right-adjoint to the functor

(5)Y:XXY -- \otimes Y : X \mapsto X \otimes Y

meaning that

(6)Hom(XY,Z)Hom(X,Z Y). \mathrm{Hom}(X\otimes Y,Z) \simeq \mathrm{Hom}(X,Z^Y) \,.

Let me here write

(7)IHom(Y,Z):=Z Y \mathrm{IHom}(Y,Z) := Z^Y

and call this object in CC the internal hom from YY to ZZ.

We are interested in the internal hom IHom(m 1,m 2)C\mathrm{IHom}(m_1,m_2) \in C between objects m 1,m 2Mm_1,m_2 \in M, i.e. in an object IHom(m 1,m 2)C\mathrm{IHom}(m_1,m_2) \in C such that

(8)Hom C(Xm 1,m 2)Hom C(X,IHom(m 1,m 2)). \mathrm{Hom}_C(X\otimes m_1, m_2) \simeq \mathrm{Hom}_C(X,\mathrm{IHom}(m_1,m_2)) \,.

By construction, the internal hom IHom(m 1,m 2)\mathrm{IHom}(m_1,m_2) behaves pretty much like a real space of homomorphism. In particular, there is an associative composition morphism

(9)IHom(m 2,m 3)IHom(m 1,m 2)IHom(m 1,m 3) \mathrm{IHom}(m_2,m_3) \otimes \mathrm{IHom}(m_1,m_2) \to \mathrm{IHom}(m_1,m_3)

in CC.

But this means that given any (nonzero) object mMm \in M, we get an internal algebra object ACA \in C by setting

(10)A=IHom(m,m). A = \mathrm{IHom}(m,m) \,.

Even better, fixing that mMm \in M, every IHom(m,m˜)\mathrm{IHom}(m,\tilde m) becomes an internal right module for this AA. Hence there is a functor

(11)F : M Mod A(C) m˜ IHom(m,m˜) \array{ F &:& M &\to& \mathrm{Mod}_A(C) \\ && \tilde m &\mapsto& \mathrm{IHom}(m,\tilde m) }

from our arbitrary module category to a module category which is a category of right AA-modules in CC. Proving the above theorem amounts to proving that this functor actually extends to an equivalence of categories.

So there is a close similarity here to the constructions discussed in the previous entry. Recall that there, the internal algebra AA was realized by two adjoint AA-modules kL A{}_k L_A and AR k{}_A R_k as

(12)A kL A A AR k. A \simeq {}_k L_A \otimes_A {}_A R_k \,.

If we pick m=L Am = L_A then clearly IHom(m,m)\mathrm{IHom}(m,m) should be nothing but kL A A AR k{}_k L_A \otimes_A {}_A R_k.

It’s sort of obvious – but I haven’t checked it.

Posted at January 3, 2006 3:17 PM UTC

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